4x^2-20x=-5x^2-6x=5

Solution for 4x^2-20x=-5x^2-6x=5 equation:

4x^2-20x=-5x^2-6x=5

We move all terms to the left:

4x^2-20x-(-5x^2-6x)=0

We get rid of parentheses

4x^2+5x^2+6x-20x=0

We add all the numbers together, and all the variables

9x^2-14x=0

a = 9; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·9·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*9}=\frac{0}{18}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*9}=\frac{28}{18}
=1+5/9
$